Calculated fallback values based on the maximum rated torque of the transmission:

• The torque loss T_l,in related to the input shaft of the transmission shall be calculated by

  $T_{\mathrm{l,in}}=\left(T_{d0}+T_{\mathrm{add}0}\right)+\left(T_{d1000}+T_{\mathrm{add}1000}\right)\times \frac{n_{\mathrm{in}}}{1000\mathrm{rpm}}+\left(f_T+f_{\mathrm{T\_add}}\right)\times T_{\mathrm{in}}$

  where:

  T_l,in

  Torque loss related to the input shaft [Nm]

  T_dx

  Drag torque at x rpm [Nm]

  T_addx

  Additional angle drive gear drag torque at x rpm [Nm]

  (if applicable)

  n_in

  Speed at the input shaft [rpm]

  f_T

  1-η

  η

  efficiency

  f_T

  0,01 for direct gear, 0,04 for indirect gears

  f_{T_add}

  0,04 for angle drive gear (if applicable)

  T_in

  Torque at the input shaft [Nm]

• For transmissions with tooth shift clutches (Synchronised Manual Transmissions (SMT), Automated Manual Transmissions or Automatic Mechanically engaged Transmissions (AMT) and Dual Clutch Transmissions (DCT)) the drag torque T_dx is calculated by

  $T_{\mathrm{dx}}=T_{d0}=T_{d1000}=10\mathrm{Nm}\times \frac{T_{\max \mathrm{in}}}{2000\mathrm{Nm}}=\mathrm{0,005}\times T_{\max \mathrm{in}}$

  where:

  T_max,in

  Maximum allowed input torque in any forward gear of transmission [Nm]

  max(T_max,in,gear)

  T_max,in,gear

  Maximum allowed input torque in gear, where gear = 1, 2, 3,… top gear). For transmissions with hydrodynamic torque converter this input torque shall be the torque at transmission input before torque converter.

• For transmissions with friction shift clutches (> 2 friction clutches) the drag torque T_dx is calculated by

  $T_{\mathrm{dx}}=T_{d0}=T_{d1000}=30\mathrm{Nm}\times \frac{T_{\max \mathrm{in}}}{2000\mathrm{Nm}}=\mathrm{0,015}\times T_{\max \mathrm{in}}$

  Here, ‘friction clutch’ is used in the context of a clutch or brake that operates with friction, and is required for sustained torque transfer in at least one gear.

• For transmissions including an angle drive (e.g. bevel gear), the additional angle drive drag torque T_addx shall be included in the calculation of T_dx:

  $T_{\mathrm{addx}}=T_{\mathrm{add}0}=T_{\mathrm{add}1000}=10\mathrm{Nm}\times \frac{T_{\max \mathrm{in}}}{2000\mathrm{Nm}}=\mathrm{0,005}\times T_{\max \mathrm{in}}$

  (only if applicable)